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  • Tippet measurements ... conversions



    Walter & Group........

    Walter Simberski, as many of you know, is not only an MCCI candidate, but also a mathematician.  I sent him a math challenge on conversions of methods of tippet measurements.

     

    This is advance information from him (I've highlighted his, "short answer" in bold blue italics :-

    Gordy,
     
    I've been working evenings at our local Calgary Stampede so I haven't been able to give full
    thought to your math challenge.
     
    There are a couple of things I have to throw out though:
     
    The first is converting between pounds and kilograms. I use a rule of 2 and 10 percent.
    For a quick calculation simply multiply or divide by 2. For example - 20 pounds is
    approximately 10 kilos and 20 kilos is approximately 40 pounds. Now, for an accurate
    value do the quick calculation and then add or subtract 10% from the result.
     
    Examples: 10 kilos is approximately 20 pounds (multiply by 2) and is exactly
      22 pounds (20 pounds plus 10%). You can add 10% first if you prefer, i.e.
      10 kilos + 10% = 11 x 2 = 22 pounds.
     
      Converting from pounds to kilos is a bit different. In our example of 22 pounds a
      quick approximation is 11 pounds (22 divided by 2). A more accurate answer is to
      subtract 10% of the result (11 - 10% = 9.9 pounds or start with 22, subtract 10%,
      and then divide by 2). For an exact answer you would have to divide by 2.2 or
      divide by 2 and then subtract 9.090909...%. For a high degree of accuracy you
      could divide by 2, subtract 10%, and then add 1% (eg. for 22 lbs this
      would be 22/2 = 11,  11 - 10% = 9.9,  9.9 + 1% = 9.999 kilos.
     
    So - for kilos to pounds multiply by 2 and add 10%. For pounds to kilos divide by
       2 and subtract 10%
     
    With regards to actual breaking strength the actual value provided by tippet
    manufacturers will depend on the statistical model they choose to use.
    They will break several samples of tippet and then apply a statistical model to
    the measured results to determine either a minimum breaking strength (which
    varies with the model chosen and the number of samples taken) or a breaking
    strength that fits within some chosen limits (e.g. guaranteed not to break at
    less than 10 pounds, plus or minus 1%, 99% of the time. The only way to
    come up with an accurate rule of thumb would be to first determine the model
    we want to use and then test tippet from many manufacturers since I am
    sure that the chemical compositions for each of their tippet materials will not
    be identical.
     
    We can talk more on this at the conclave.
     
    Cheers
     
    Walter
     
    ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
    Walter .....
     
    Thanks !   That's a good start.   See you at the Conclave.
     
    Gordy