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  • Re: Fly Casting, "Math"



    Tom...

    Check out my additional notes below our answers to # 9.) in green. (Scroll way down for details.)

                                                             Gordy




     


    From: "Gordon Hill" <hillshead@xxxxxxx>
    To: cooper@xxxxxxxxxxxxxxxxxx
    Subject: Re: Fly Casting, "Math"
    Date: Mon, 22 May 2006 10:28:23 -0400

    Tom...

    My comments in BOLD CAPS.

    You did really well !!!!   

                                                     Gordy




     


    From: "North Fork Flies - Tom Cooper" <cooper@xxxxxxxxxxxxxxxxxx>
    Reply-To: "North Fork Flies - Tom Cooper" <cooper@xxxxxxxxxxxxxxxxxx>
    To: "Gordon Hill" <hillshead@xxxxxxx>
    Subject: Re: Fly Casting, "Math"
    Date: Mon, 22 May 2006 03:16:12 -0400

    My answers are in red
    ----- Original Message -----
    Sent: Sunday, May 21, 2006 8:14 AM
    Subject: Fly Casting, "Math"

    Jerry...

    My server may have prevented some of the Group from getting my questions on, "Fly Casting Math."  Would you help by sending this out ?  Of these 9 questions, I'd expect an MCI candidate to correctly answer 6 of them (*)  An exceptional candidate to be correct on 8.

    1.)* You are given the speed of the fly leg of a loop for a cast with no shooting of line. What is the formula for calculating the loop speed?

     Loop speed is 1/2 of the fly leg speed.

    YES.

    2.) Now you have a cast made with a line shoot.  You know the speed of the fly leg and the speed of the rod leg.  What formula is used for determining loop speed ?

    Loop speed is 1/2 of the fly leg speed + the rod leg speed

    IT'S:  FLY LEG SPEED + ROD LEG SPEED DIVIDED BY 2.

    3.)* You are casting a fly tied on a # 12 hook.  What formula or, "rule" might you sue to help determine the approximate, "X" size for your class tippet ?

    Rule of 3's. Divide fly size by 3 (or 4) or a 4X tippet

    YES.

    4.)* What formula or, "rule" would you use for determining the diameter of your 5X tippet ?

    Subtract 5, The X size, from .011 (the diameter of 0X tippet) or .006.

    YES. (ANOTHER WAY TO PUT IT IS TO SUBTRACT THE X NUMBER FROM 11 AND DIVIDE BY 1000.)

    5.)* You know your tippet size to be 4X.  What formula might you use to determine its pound breaking strength ?

    Sorry to say I don't know this one, but with the wide range of test breaking strengths does a rule of thumb work?

    "RULE OF 9'S"...SUBTRACT THE X NUMBER FROM NINE AND YOU GET AN APPROXIMATE VALUE FOR BREAKING STRENGTH.  (LESS RELIABLE THAN IT USED TO BE PRIOR TO THE NEW TIPPET MATERIALS MANY OF WHICH ARE STRONGER/DIAMETER.)

    6.)* What, "rule" or formula might you use to come up with the weight in grains for the first 30' of your #6 designated fly line ? (A rough approximation)

    Line weight X 30 or 6 X 30 = 180.  I like to use ((Line Weight X 25) + 25) or 6X25 = 150 +25 = 175  It is more accurate on lighter weights.

    I AGREE. USING 30 GETS YOU CLOSE IN RANGE FOR A 4 WT. LINE.  IT IS LESS ACCURATE AS YOU GO IN EITHER DIRECTION FROM THAT. 

    7.) What is the so-called, "IGFA Formula" for determining the weight in pounds of a game fish ?  You have only the length of the fish and the girth of the fish measured in inches.

    Girth Squared X Length/800 = Weight

    YES.

    8.)* Can you come up with a very general, "rule of thumb" to describe a typical fly leader in terms of percentage for butt section, tapered section, and tippet section ?

    60 - 20 - 20

    YES.

    9.) You are trying for maximum distance.  can you come up with a simple formula for determining the approximate length of your shoot when knowing the amount of line carried on your last back cast ?

    Back cast length x 1.333 = total forward cast length.

    I HAVE NOT HEARD OF THAT FORMULA.....I'LL TRY IT AND SEE. (DO YOU HAVE A REFERENCE FOR IT ?)

    I'VE USED:  50% OF THE LINE CARRIED FOR THE LENGTH OF THE SHOOT. (THE LENGTH OF THE SHOOT IS THE VALUE I ASKED FOR IN THE QUESTION.)

    After typing the above comment, I went out and we tested it.  I took note of the fact that the 1.333 formula means this:

    The caster can carry 60' on his last back cast.  His total distance for his presentation would then be 60 X 1.333 which is 70.9 feet.

    Now most CCI candidates who pass make a 75' distance cast when carrying about 50'. Your 1.333 formula would mean that they could achieve only 1.333 X 50 = 66.5'

     I can make a 90' cast routinely by carrying 60'.  This makes the 1.333 formula short of the mark, as I see it.  (Most MCI's I've coached can do the same thing once they reach test level.)

                                                            Gordy

     

    Tom Cooper

    * expected of an MCI candidate.

                                                             Gordy